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what is the solution to 16x^3-2=0
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It's going to be an extremely small decimal are you sure this is the correct equation?
yea the teacher said decimal answers should be rounded to 2 decimal places
Do you have an "cannot be determined" option?
no
Ok so what I got so far is \[x^3=0.125\]
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so now all you have to do is find the cube root of 0.125 to find x
ok thanks for helping me out
Anytime! :)
so how would you find the solution for x^4-6^2=27
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