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A 5.0 kg box falls from a height of 20.0m. Just before hitting the ground what is the object's kinetic energy?
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I know the formula is 1/2mv^2 but how do you find the answer without the velocity?
to find final velocity,use 3rd equation of motion :- \[\large \bf v^2=u^2+2as\] where, u=0 , a=10 m/s^2 and s=20 m
hope you can solve your question ! @endoftime14
Thank you!! :D
your welcome :)
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