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Mathematics 7 Online
OpenStudy (anonymous):

prove that A x B = -B x A..

OpenStudy (ahsome):

Use any values for A and B, and see if it is right Image \(A\) is 5 and \(B\) is 6 \(A \times B = -B \times A\) Sub the previous values \(5\times6=-6\times5\) See if it is right

OpenStudy (anonymous):

i don't think so if it is right.. Can you please use this value to prove.. A=Axax, Ayay, Azaz and B= Bxax, Byay, Bzaz

OpenStudy (ahsome):

What is axax, ayay, etc...?

OpenStudy (anonymous):

that are vectors

OpenStudy (perl):

this is A cross product B

OpenStudy (perl):

Let a=<a_1,a_2,a_3> and b=<b_1,b_2,b_3> a x b = < a_2 * b_3 - a_3*b_2 , a_3*b1 - a_1*b3, a_1*b_2 - a_2*b_1>

OpenStudy (perl):

now use this formula to show that -b x a = a x b

OpenStudy (anonymous):

thankss, i'm solving it right now..

OpenStudy (anonymous):

figuer out 5 times 6= and then figure out what -6 times 5=

OpenStudy (anonymous):

@perl : can you please continue answering this, still i can't understand

OpenStudy (anonymous):

Is that A and B stands for vectors? other wise it's wrong question!!!!

OpenStudy (anonymous):

yes..

OpenStudy (anonymous):

alright it is a cross product of two vectors!! let c be the cross product of the two vectos|dw:1417697943681:dw|

OpenStudy (anonymous):

can you just explain using these.. A=Axax, Ayay, Azaz and B= Bxax, Byay, Bzaz

OpenStudy (anonymous):

ok let A(1,2,1) and B(-1,0,1) |dw:1417698688017:dw|

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