Question

the sum of four consecutive integers is 410

Answer 1

and what is the problem???

Answer 2

(x-1)+x+(x+1)+(x+2)=410

where (x-1) is the first number.

Answer 3

(x-1)+x+(x+1)+(x+2)=410
x-1+x+x+1+x+2=410
4x+2=410
4x=408
x=102

and x-1 , the first number is 101,

so the numbers are:
101, 102, 103, 104.