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Imaginary numbers?
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i, i+1, 3i-4, etc...
simplify each expression (-1+2i)(3+10i) (-1+3i)^2 (5-3i)(5+3i)
(-1+2i)(3+10i) -3-10i+6i+20i^2 -3-4i+20i^2 -3-4i+20(-1) -3-4i-20 -23-4i. that is it
Okay what about the other two?
use a rule, (a-b)^2=a^2-2ab+b^2 (-1+3i)^2 (-1)^2+2(-1)(3i)+(3i)^2 1+2(-1)(3i)+(3i)^2 1-6i+(3i)^2 1-6i+9(i)^2 1-6i+9(-1) 1-6i-9 -8-6i
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(5-3i)(5+3i) use a rule (a-b)(a+b)=a^2-b^2 (5)^2-(3i)^2 25-9(-1) 25+9 36.
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