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OpenStudy (anonymous):
Find all solutions in the equation. Need some guidance! Sin^2x + sinx = 0
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OpenStudy (anonymous):
sinx(sinx+1)=0 => six=0 or sinx+1=0=> sinx=-1
OpenStudy (anonymous):
Can you explain to me how to work it out step by step. My problem is that I do not really know how to work the problems out D:
OpenStudy (anonymous):
@iGreen Could you help a friend out?
OpenStudy (igreen):
Sorry, I gotta go.. http://www.wolframalpha.com/input/?i=find+all+solutions+Sin%5E2x+%2B+sinx+%3D+0
OpenStudy (anonymous):
Its fine!
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OpenStudy (anonymous):
Found the answer elsewhere: http://openstudy.com/study#/updates/5096c663e4b02ec0829be918 Question closed
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