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SAT&ACT Math 13 Online
OpenStudy (aripotta):

Question in comments~

OpenStudy (aripotta):

OpenStudy (adamaero):

Okay, so there is two weeks of time (total time for everyone staying at the hotel) and you want to find when there was potential for no families staying there

OpenStudy (adamaero):

you should start by looking at the two families with the lowest time spent in the hotel

OpenStudy (aripotta):

it's asking which night had only one family staying

OpenStudy (aripotta):

there's callan at 5 and liu at 6

OpenStudy (adamaero):

ya, I'm wrong try starting at day one with the largest family I know how to get the answer, but it'd take time explaining & gtg

OpenStudy (anonymous):

I got my guess but have a feeling it is wrong what I did was lay out the nights the families stayed. J- 1-10 2-11 3-12 4-13 5-14 C- 1-5 2-6 3-7 4-8 5-9 6-10 7-11 8-12 9-13 10-14 E- 1-8 2-9 3-10 4-11 5-12 6-13 7-14 L- 1-6 2-7 3-8 4-9 5-10 6-11 7-12 8-13 9-14 B- 1-8 2-9 3-10 4-11 5-12 6-13 7-14 Then crossed out the days that the families could have possibly started staying so all on day 1 was crossed off until none had days in common

OpenStudy (anonymous):

Sorry if that doesn't help confusing way of looking at it but i got 10 being C was the only family that started that day

OpenStudy (aripotta):

well the answer is a :/

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