What would be the discriminant of h(x)=x^2-2x-35? How many complex solutions will it have? And can it be solved by the Quadratic Formula.
Yes, this is easy stuff but its been so long that i forgot how to do it. Thanks

Question

What would be the discriminant of h(x)=x^2-2x-35? How many complex solutions will it have? And can it be solved by the Quadratic Formula.
Yes, this is easy stuff but its been so long that i forgot how to do it. Thanks

anonymous · Answer

Your function h has two real roots, since
$$
h(x)=x^2-2 x-35=(x-7) (x+5)
$$

anonymous · Answer

If you want to do it using the quadratic formula,
$$
\Delta = b^2 - 4 a c= 4+140=144\
\sqrt {\Delta}=12\
x=\frac { 2\pm 12     }{2}=1\pm 6\
x=7\
x=-5

$$