The area of a rectangle is represented by x^2-2x-8 find an expression for the length of each side if x=5
hmmm
sounds like you need to factor x^2-2x-8 as a first step
area=x^2-2x-8 LW=( )( ) <--this is the factored form of the area
so what two numbers multiply to be -8 and add up to be -2?
@Ednac are you there?
there is nothing to factor from the initial problem @myininaya
yes you need to factor x^2-2x-8
to find the length and the width of the rectangle
it is as factored as it gets
-4(2)=-8 -4+2=-2 it can be factored
so given that the factored form of x^2-2x-8 is ?
is there a term that can be taken out fropm all of the terms other than one?
Where are you going with the fact that it is factorable
to find the length and width of the rectangle with area=x^2-2x-8
Area of rectangle=Length * Wdith x^2-2x-8 =( )* ( )
now I basically told you the factored form
since I said -4(2)=-8 and -4+2=-2
so x^2-2x-8=(x-4)(x+2)
now you have the length and the width
your question wants to know the length and the width when x=5
awesome job at explaining @myininaya
I tried (or try)
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