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Chemistry 15 Online
OpenStudy (anonymous):

Cr2O7^2- + Hg → Hg^2+ + Cr^3+ (basic solution) I got 14H2O + 2Cr2O7^2- + 3Hg → 3Hg^2+ + 2Cr^3+ 28OH- but an answer key has something else and I can’t figure out how I’m wrong

OpenStudy (anonymous):

the Cr your problem ( 2 Cr2) this is 4 Cr

OpenStudy (anonymous):

........+ 4 Cr^3+28OH^-

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