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Complete the equation for the linear function whose graph contains the points (−1, −2) and (3, 10). y+____=____(x+1)
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Correction- (-1,-2) and (3,10)
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\(\large\tt \begin{align} \color{black}{(x_1,y_1)=(-1,-2)\\ (x_2,y_2)=(3,10)\\ y-y_1=m(x-x_1)\\~\\~\\ m=\dfrac{y_1-y_2}{x_1-x_2}\\ =\dfrac{-2-10}{-1-3}\\ =\dfrac{-12}{-4}\\ =3\\~\\~\\ y-(-2)=3(x-(-1))\\ y+2=3(x+1)\\ }\end{align}\)
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