Help medal! How to factor with 4 numbers?

like this: 16v^3 -2v^2 + 40v-5

Question

Help medal! How to factor with 4 numbers? 

like this:  16v^3 -2v^2 + 40v-5

mathmate · Answer

Hint: 
$16v^3 -2v^2 + 40v-5$ = $2v^2(8v -1) + 5(8v-1)$
You can complete the factorization by grouping.

anonymous · Answer

Thanks... but what do you do after  its  2v^2 (8v-1)  + 5 (8v-1) ??

mathmate · Answer

You would find that (8v-1) is a common factor between the two terms.
Therefore extract (8v-1) as a common factor and the factorization is complete.
For example:
5x(2x+1)-3(2x+1)=(2x+1)(5x-3)

anonymous · Answer

So what is the answer? Exactly?

mathmate · Answer

Study my last two posts and work out your answer.  I will be glad to tell you if it is correct.

anonymous · Answer

So (8v-1) is the common factor which means is the answer?