Question

Help medal! How to factor with 4 numbers?

like this: 16v^3 -2v^2 + 40v-5

Answer 1

Hint:
\(16v^3 -2v^2 + 40v-5\) = \(2v^2(8v -1) + 5(8v-1)\)
You can complete the factorization by grouping.

Answer 2

Thanks... but what do you do after its 2v^2 (8v-1) + 5 (8v-1) ??

Answer 3

You would find that (8v-1) is a common factor between the two terms.
Therefore extract (8v-1) as a common factor and the factorization is complete.
For example:
5x(2x+1)-3(2x+1)=(2x+1)(5x-3)

Answer 4

So what is the answer? Exactly?

Answer 5

Study my last two posts and work out your answer. I will be glad to tell you if it is correct.

Answer 6

So (8v-1) is the common factor which means is the answer?