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Help please.. Evaluate the logarithm. log6 1/36
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\[\log_{6} \frac{ 1 }{ 36 }\]
write 1/36 as a power of 6 \[\frac{1}{36} = 6^{-2}\]
the base of the log and base of the exponent are the same so \[\log_{a} (a^x) = x\] apply the law to your question
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