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OpenStudy (anonymous):
search for a complex number z=((2+2j)^2014) eksponential shaped presentation
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OpenStudy (anonymous):
Convert \(2+2j\) into trigonometric/polar form first. It'll make things easier. \[w=x+jy=re^{it}~~\text{with}~~\begin{cases}r^2=x^2+y^2\\\tan t=\dfrac{y}{x}\end{cases}\]
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