Question

14ab3/7a-2b-1

Answer 1

i am going to make a guess that these are exponents and it s really
\[\huge \frac{14ab^3}{7a^{-2}b^{-1}}\]

Answer 2

yes

Answer 3

bring the negative exponents up and make them positive
also 7 goes in to 14 twice
you get
\[\huge 2aa^2b^3b\] then add the exponents to get
\[\huge 2a^2b^4\]

Answer 4

ok

Answer 5

clear enough? or confused?

Answer 6

I think I got it

Answer 7

k good