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3x/2 - x = x/6 - 4/3 Solve
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\[\frac{ 3x }{ 2 } - x - \frac{ x }{ 6 } = \frac{ -4 }{ 3 }\]
How do you solve it
Take lcm of 2,6, 1 (i.e 12) \[\frac{ 6*(3x) }{ 12 } - \frac{ 12*x }{ 12 } - \frac{ 2*x }{ 12 } = \frac{ -4 }{ 3 }\] \[\frac{ 18x - 12x - 2x }{ 12 } = \frac{ -4 }{ 3 }\] solve for x
The answer is -4/3
Is this right
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\[\frac{ 4x }{ 12 }= \frac{ -4 }{ 3 }\] \[ 4x = \frac{ -4 *12}{ 3 }\] \[ x = \frac{ -4 *12}{ 3 *4 }\] \[ x = \frac{ -1 *12}{ 3 }\] \[ x = \frac{ -1 *4}{ 1 }\] \[ x = -4\]
Alright I see how to do it
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