Question

Solve the equation. |k + 6| = 3
{–3, 9}
{–3, 3}
{–9, –3}
{all real numbers greater than or equal to –9 and less than or equal to –3}

Answer 1

use the theorem:
\[\large |a|= b\qquad\Leftrightarrow\qquad a=b\quad\vee\quad a=-b \]