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Simplify. Assume all variables are nonzeros (8x^3y/2)^2 PLEASE HELP !
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\[\frac{8x^3y}{2}=4x^2y\] is start then square that one
How did you get that?
i divided eight by two and got four
Ooh Okay. Got it. So once i do that what do i do next?
\[(4x^3y)^2=16x^6y^2\] is the last step
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Okay Thanks so MUCH!!
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