Question

2x^2+x-3
Factor

Answer 1

What you can do when a>1 is do the borrow payback method.

Multiply a by c.

x^2+x-6=0

Factor that to (x-2)(x+3)

Now plug back a into the factors

(2x-2)(2x+3)

Divide the first one by 2.

(x-1)(2x+3)

Answer 2

general equation
ax^2 + bx + c = 0
what are the factors of a*c that add up to b

Answer 3

I'm only assuming she doesn't know how to factor it when a>1. But anyways, if a=1, then follow @triciaal

Answer 4

thank you!!

Answer 5

Welcome. Any other questions?

Answer 6

would you know how to do this
f(x)=x^4+4x^3+3x^2-2x-6 Use SYNTHETIC DIVISION and remainder theorem to find f(4)

Answer 7

Hmm, never heard of those. But wouldn't mind learning it, which I probably could in 20ish minutes

Answer 8

I'll give it a try.

Answer 9

well i wouldnt want to make you do that ha

Answer 10

Nah, I don't mind. Unless someone else can explain it. I want to learn too, lol.

Answer 11

f(4) means to let x = 4 in the polynomial

Answer 12

but every one equals 256

Answer 13

when f(x) = 0 then x is a factor
when f(x) is not 0 you have a remainder

Answer 14

example f(0) for this problem = -6
hint the constant is -6 so the factors will be factors of 6 1,2,3, 6

Answer 15

also need to check the sign
f(x) + + + - -
no no yes no possible one positive real
f(-x) + - + + -
yes yes no yes possible three negative

Answer 16

I'm still not really sure what to do

Answer 17

f(4)
(4)^4 + 4(4)^3 + 3(4)^2- 2(4)-6 =

divide the function by x^2 to get x^2 + 4x + 3 remainder -2x-6
factor this quadratic
(x+3)(x + 1) remainder is -2(x + 3)

Answer 18

why divide by x^2?

Answer 19

x^4 should be 4 factors x^2 will give a quadratic to factor

need to get the official reason to answer you better

Answer 20

what do I put for f(4)=? then ?

Answer 21

f(x)=x^4+4x^3+3x^2-2x-6 Use SYNTHETIC DIVISION
one factor is (x + 3)