Question

f(x)=x^2+6x-16, I need to convert this to vertex form. HELP PLS!!!!!!

Answer 1

do you know how to complete the square?

Answer 2

no :(

Answer 3

I was looking on youtube for explanations but I couldnt find any

Answer 4

@Zale101

Answer 5

Is the bottom the answer?

Answer 6

cause I need to explain how to solve it

Answer 7

\[x^2+6x-16=y\]
\[x^2+6x-16+16=y+16\]
\[(x^2+6x)=y+16\]Take half of the coefficient and then square, the coefficient in this case is 6

Answer 8

http://www.mathsisfun.com/algebra/completing-square.html

Answer 9

can you ake half of the coeffeincet and then square it? \((\frac{ 6 }{ 2 })^2\)

Answer 10

take*

Answer 11

\[(x^2+6x+(\frac{ 6 }{ 2 })^{2})=y+16\]

Answer 12

Do I solve this and get the answer? @Zale101

Answer 13

That's just part of the process.

Answer 14

dang

Answer 15

(6/2)^2=?