Question

solve (6/t)-2/(t-1)=1

Answer 1

so im guessing you have to solve for t?

Answer 2

welcome to OS btw

Answer 3

\[(6-t) - \frac{ 2 }{ (t-1) } = 1\]
\[\frac{ (6-t)*(t-1) - 2 }{ (t-1) } = 1\]

Answer 4

\[\frac{ (6t-t^2-6 - t) - 2 }{ (t-1) } = 1\]
\[\frac{ (5t-t^2-8) }{ (t-1) } = 1\]
\[ (5t-t^2-8) = 1 *(t-1)\]
\[ (5t-t^2-8) = t-1\]
\[ 5t-t^2-8 - (t-1) = 0\]
\[ 4t-t^2-7 = 0\]
\[ t^2- 4t + 7 = 0\]

Answer 5

solve the quadratic