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Mathematics 17 Online
OpenStudy (anonymous):

Anyone know how to Graph Quadratic Equation? Question in picctures. Please someone help.

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

Some simple things to do to try and pinpoint which graph is correct. (1) Test for the intercept values. Set x=0 to find where the graph should cross the y-axis. Set y=0 to find where the graph should cross the x-axis. (2) For an equation: y(x) = Ax^2 + Bx + C, you can find -B/2A. This represents the x-value of the vertex. You can substitute this x value back into y(x) to find the y-value and, therefore, the vertex coordinate. (3) Look at A in the equation I gave in (2). If A is positive, the graph curves upward. If A is negative, the graph curves downward.

OpenStudy (anonymous):

its c then?

OpenStudy (anonymous):

@nincompoop @Mendicant_Bias @quin100 @rosho @Pompeii00 @z89065 @kelsey4twenty @love_to_love_you

OpenStudy (anonymous):

@Nnesha

OpenStudy (anonymous):

@Tierra8

OpenStudy (anonymous):

@sleepyjess

OpenStudy (anonymous):

@surryyy

OpenStudy (anonymous):

@yoitsren

OpenStudy (anonymous):

Yep, you're right!

OpenStudy (anonymous):

for real?

OpenStudy (anonymous):

OpenStudy (anonymous):

Just substitute in your values of x into the function. You'll see it gives you 6, 2, 0, 0

OpenStudy (anonymous):

keep helping me please

OpenStudy (anonymous):

OpenStudy (anonymous):

@Pompeii00

OpenStudy (anonymous):

@Natasha.g.2013

OpenStudy (anonymous):

@yoitsren

OpenStudy (anonymous):

@No.name

OpenStudy (anonymous):

@sharonholmes1

OpenStudy (anonymous):

@Destinymasha

OpenStudy (anonymous):

@chosenmatt

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