Question

factor 4cos^2x-4sinx-5=0

Answer 1

\[4\cos ^2x-4\sin x-5=0\]
\[4(1-\sin ^2x)-4\sin x-5=0\]
\[4-4\sin ^2x-4\sin x-5=0\]

Answer 2

\[-4\sin ^2x-4sinx-1=0\]

Answer 3

\[4\sin ^2x+4\sin x+1=0\]

Answer 4

Factor that.

Answer 5

how did you get a sin from a cos?