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find the area in oval limacon r=5+cos(theta)
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it's a circle with radius 5.
need the area
actually my bad, doesn't look like a circle though.
okk
anyway, area = integral (1/2) (5 + cos(theta))^2 dtheta, from 0 to 2pi
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try \[\int\limits_{0}^{2\pi} 0.5(5+\cos \theta)^2d\]
do the math and area = (51/2)pi
which is what she said
yess thank you
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