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Help please, The number of bacteria N at a certain time t is given by N = 100et /10, when there are 100 bacteria at time t = 0 hours. Find how many hours t it takes for the bacteria to double (that is, increase from 100 to 200 bacteria). [Use either e2 = 9 or ln(2) ≈ 0.7 to approximate your answer as appropriate.]
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