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x^2 + 6x + 8 = 0
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\[ \begin{split} x^2+6x+8 &= x^2+2x+4x+4(2) \\ &= x(x+2)+4(x+2) \\ &= (x+4)(x+2) \end{split} \]
\[ \begin{split} (x+4)(x+2) = 0 &\implies x+4=0\quad&\text{or}&\quad x+2=0 \\ &\implies x=-4\quad &\text{or}&\quad x=-2 \end{split} \]
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