Question

2tan^2xsinx-tan^2x=0

Answer 1

2tan^2xsinx=tan^2x
2sinx=tan^2x/tan^2x
2sinx=1
sinx=1/2
x=pi/6, 5pi/6

Answer 2

Just for clarification when you move the tangents to one side they cancel out and all that's left to solve is the sin part right?

Answer 3

yup

Answer 4

Wait so where does the two go??

Answer 5

Nvr I see where it went

Answer 6

\[2 \tan^2(x) \sin(x)-\tan^2(x)=0 \\ \text{ factor left hand expression } \\ \tan^2(x)[2 \sin(x)-1]=0 \\ \text{ two equations to solve } \tan^2(x)=0 \text{ or } 2\sin(x)-1=0\]