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Can someone walk me through: 6^(2x)=3 square root of 36
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ok
\[6^{2x}=\sqrt[3]{36}\]
ln(x^b) = b* ln(x)
is this is the Q?
anyway take the (ln) for both side\[\ln(6^{2x})=\ln(\sqrt[3]{36})\]
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\[2x \ln(6)=\ln(\sqrt[3]{36)}\] \[x=\frac{ \ln(\sqrt[3]{36} )}{ 2\ln(6)}\]
\[5(2^{2x})+17(2^{x})=-6\]
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