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Given g(x)=1.1845-log x determine for what value of x that g(x)=1
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g(x) = 1 = 1.1845 - log(x)
log(x) = 1.1845 - 1 log(x) = 0.1845
10^log(x) = x = 10^(0.1845) = calculator number
thanks. Do you know of an instructional site that teaches you how to use your calculator? I am unable to move past the basic keys to solve equations.
should be a button that looks like y^x or x^y so you can solve x =10^0.1845
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not sure, you would have to search for your specific calculator instructions.
I will Thank you so much.
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