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if the geometric mean of two numbers is 6 and its arithmetic mean is 10 find the numbers.!!
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let the numbers be x and y, then x+y=2*10 x*y=6^2 solve for x and y
Solve it for me please.
here will come a quadratic equation if we put x=36/y in equation 1
correct.
\[\frac{ 36 }{ y }+y=20\] \[y^2-20y+36=0\] \[y^2-2y-18y+36=0 \] now you can solve.
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then it will give us 2 value for y.. i want one.
when y=2 ,x=36/2=18 when y=18, x=36/2 =18 so only order is different. hence numbers are 2 and 18
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