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for what values of f(x) = |x - 1| differentiable?
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well think about f(x)=|x-1| for which value of x is there a sharp turn?
When you can name that value, then you have found the only value of x which f is not differentiable
at 1
what does that satement mean exactly?
it is not differential at x=1
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\[\frac{ d }{ dx }\left| x-a \right|=\frac{ x-a }{ \left| x-a \right| }\frac{ d }{ dx }\left( x-a \right)\]
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