Question

Help-I need to graph sin and cos type 2

y=1/2sin(1/2x)

0 | 0
pi/2 | 2
pi | 0
3pi/2| -2
2pi | 0

For some reason I am wrong?

Can someone help me.

Answer 1

amplitude = 1/2 not 2

and period is 4pi not 2pi

Answer 2

period = 2pi/(1/2) = 4pi

Answer 3

so how would it be graphed? this is what my graph looks like.

Answer 4

\[y = A \sin(Bx)\]
Period = 2pi/B

0 | 0
P/4 | A
P/2 | 0
3P/4 | -A
P | 0

Answer 5

To draw the graph, plot all
x
-intercepts, minima, and maxima within one period.


It says I'm wrong. I've literally been stuck on these sorts of problems for days.

Answer 6

your amplitude is right, but your period is still off

B = 1/2

Period = 2pi/B = 2pi/(1/2) = 4pi

Answer 7

0 | 0
Period/4 | A
Period/2 | 0
3/4 Period | -A
Period | 0