F = (11y^2 + ln(3x^2 + 1)) i − (11x^2 + sin(8y^2)) j

(a) Find the 2-dimensional or scalar curl.

(b) For constant A 0, consider the three closed triangular paths:
C1: From the origin to (A, A/2) to (A/2, A) to the origin
C2: From the origin to (−A, −A/2) to (−A/2, −A) to the origin
C3: From the origin to (−A/2, A) to (−A, A/2) to the origin

Arrange the three line integrals L1, L2, and L3 where
L_n = integral F · dr

Question

F = (11y^2 + ln(3x^2 + 1)) i  − (11x^2 + sin(8y^2)) j 
 

(a) Find the 2-dimensional or scalar curl.
 
 

(b) For constant A > 0, consider the three closed triangular paths:
C1: From the origin to (A, A/2) to (A/2, A) to the origin 
C2: From the origin to (−A, −A/2) to (−A/2, −A) to the origin 
C3: From the origin to (−A/2, A) to (−A, A/2) to the origin

Arrange the three line integrals L1, L2, and L3 where 
L_n = integral F · dr

anonymous · Answer

for part a) I'm getting the scarl curl to be 22x-22y but it marking it wrong.

anonymous · Answer

@eliassaab what am I doing wrong?

anonymous · Answer

I also tried 22x+22y but its also wrong

anonymous · Answer

and for part b I'm getting L1<L3<L2. Am I right?

anonymous · Answer

@dan815 can you help me please?

anonymous · Answer

The scalar curl is -22 x - 22 y

anonymous · Answer

thanks @eliassaab do you think part b is right?