Question

Ok, sanity check. I'm calculating the surface area of a torus. I'm pretty far into it (see image). Am I on the right path?

Answer 1

Its to fuzzy

Answer 2

Fuzzy?

Answer 3

I got something like \(64\pi\).

Answer 4

Same approach, then? I just wanted to make sure I wasn't heading down another rabbit hole. This latest assignment has had a few of them.

Answer 5

@across Sanity restored. It turns out it was 32pi^2. Now to work this charlie horse out of my hand. :P

Answer 6

Yes, sorry, I somehow multiplied by two over pi.