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if log3=x and log7=y, then log63 is......
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Hint: 63 = 9*7 = 3^2*7
x^2y?
@jim_thompson5910
that allows us to say \[\Large \log(63) = \log(3^2*7)\]
what can we do next?
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well log3 ^2 is x sooooo x *x*y
@jim_thompson5910
do you know the log rules?
kind of......
review these rules http://www.purplemath.com/modules/logrules.htm
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hopefully they seem familiar
2x+y?
very good
so thats the answer ?
yeah
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ok thank you so much!!!!
np
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