Question

how to solve this system of equations using substitution method : 4y=x 3x-y=70

Answer 1

K so x
=4y right plug 4y in the original eqn(3x-y=70) for x
Make sense so far/ :)

Answer 2

4y = x or x = 4y

so we can replace every 'x' in the second equation with 4y

3x-y=70

3(4y)-y=70 ... replace x with 4y

12y - y = 70

solve for y

Answer 3

thank you so much