College Algebra: 2X2 Non-Linear Systems.
I need to solve this system algebraically and then graph both of the equations on the same coordinate system to support my solution. I'll write the problem in comments.

Question

College Algebra: 2X2 Non-Linear Systems.
I need to solve this system algebraically and then graph both of the equations on the same coordinate system to support my solution. I'll write the problem in comments.

anonymous · Answer

$$y=x^{3}-x$$
$$y=x$$

anonymous · Answer

Just substitute y=x into the first equation. So you have $$x=x ^{3}-x$$$$0=x ^{3}-2x$$$$(x ^{2}-2)(x)=0$$$$x ^{2}-2=0$$$$x ^{2}=2$$$$x=\pm \sqrt{2}$$ Find the value of y for x=0 and x=+/- 2^(1/2) 
 
From equation
$$y=x$$

For x=0 

y=0

For$$x=\pm \sqrt{2}$$
$$y=\pm \sqrt{2}$$