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What is the inverse of the given relation? y = 7x2 – 3
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y+2=7x^2 so (y+2/7)=x^2 so x=sqr ((y+2/7)) then x replace to y then we have: y=sqr ((x+2/7))
Oh whoops!! the 2 is an exponent! Totally my fault!!
So, what is the inverse of 7x^2-3,
after operation above: we have: y=sqr ((x+2/7))
To find the inverse: Replace f(x) with y Switch x's and y's, so put x where y is and x where y is. Solve for y Replace y with f^-1(x)
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Thank you so much!!!!!! And to find the inverse of a problem such as y=-4x^2-4 or something, I would do the opposite?
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