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Find the indicated z score. The standard normal distribution with the mean 0 and standard deviation 1. Decimal---> 0.8997
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so it looks you want to solve P ( Z < a ) = .8997 , and you need to find 'a'
did you look on the table
you can also use TI 83 there is a command called invNorm , if you press 2nd Vars 3: invNorm
invNorm( .8997) = ?
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1.27 or 1.28?
1.28 is fine
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