Question

An object is thrown upward from the top of a building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadratic equation When will the object hit the ground?

Answer 1

How tall is the building?

Answer 2

I need more info

Answer 3

160 feet

Answer 4

so the object is thrown up more or down?

Answer 5

The height h of the object after t seconds is given by the quadratic equation h=16t^2+48t+160

Answer 6

Cool

Answer 7

When h = 0
h = -16t^2 + 48t + 160 = 0
Solve for t

Answer 8

What do you think it is?

Answer 9

im not sure how to solve for t