Question

Fan + Medal

Answer 1

:( I forgot how to do that

Answer 2

i can help

Answer 3

nvm

Answer 4

formula is where co-ordinates are
\( (a_1,a_2) ~~(b_1.b_2) ~~and ~~(c_1,c_2)\)
\(\large\tt \begin{align} \color{black}{area=\left |\dfrac{a_1(b_2-c_2)+b_1(c_2-a_2)+c_1(a_2-b_2)}{2}\right| \\~\\

}\end{align}\)
your co-ordinates are
\( (x_1,y_2) ~~(x_1.y_1) ~~and ~~(x_3,y_3)\)

\(\large\tt \begin{align} \color{black}{area=\left |\dfrac{x_1(y_1-y_3)+x_1(y_3-y_2)+x_3(y_2-y_1)}{2}\right| \\~\\
=\left |\dfrac{x_1y_1-x_1y_3+x_1y_3-x_1y_2+x_3y_2-x_3y_1}{2}\right| \\~\\
=\left |\dfrac{x_1y_1-x_1y_2+x_3y_2-x_3y_1}{2}\right| \\~\\
=\left |\dfrac{x_1(y_1-y_2)+x_3(y_2-y_1)}{2}\right| \\~\\
=\left |\dfrac{-x_1(y_2-y_1)+x_3(y_2-y_1)}{2}\right| \\~\\
=\left |\dfrac{(x_3-x_1)(y_2-y_1)}{2}\right| \\~\\
}\end{align}\)

Answer 5

How do I take that and make it look like one of the choices

Answer 6

@mathmath333

Answer 7

u mean the the vertical bars

\(A=\Huge \left | \right|\)

Answer 8

they are included so that area is always positive
look at your 4th option btw

Answer 9

The only thing that confuses me is the 2

Answer 10

\(\large\tt \begin{align} \color{black}{area=\left |\dfrac{(x_3-x_1)(y_2-y_1)}{2}\right| \\~\\}\end{align}\)
this can be written as

this
\(\large\tt \begin{align} \color{black}{area=\dfrac{1}{2}|(x_3-x_1)(y_2-y_1)|}\end{align}\)