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Solve x2 + 6x + 7 = 0. can anyone help
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\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] can you insert for variables a=1 b=6 c=7
so the answer would be
close you're missing a number though
would it be over 2
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\[\frac{ -6 \pm \sqrt {6^2-4(1)(7)} }{ 2(1) }\] \[\frac{ -6 \pm \sqrt {36-28} }{ 2 }\] \[\frac{ -6 \pm \sqrt {8} }{ 2 }\]
What does 8 factor out to?
the result product would be 2
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