Question

Hello, I need help with an integral :)

\[\int\limits_{0}^{\sqrt{2}}x~e ^{-(x^2/2)}dx\]

Answer 1

@uri @Abhisar

Answer 2

let u = -(x^2/2) ?

Answer 3

ok
then du = -x dx ?

Answer 4

yeah, then you ahve \(-du = x~dx\)

So you have \(\displaystyle-\int e^u ~du\)

Answer 5

have*

Answer 6

ok then I'll get - e^(-x^2/2) from 0 to sqrt2 ?

Answer 7

Yeah

Answer 8

oooooooooo I see what I did wrong before!
thank you! :)

Answer 9

no problem