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If f(x) varies directly with x2, and f(x) = 72 when x = 6, find the value of f(3) MEDAL
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Varies directly just means proportional.\[ f(x)=kx^2 \]
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They gave us \(f(6)=72\), which means \[ 72=k(6)^2 \]Allowing us to find \(k\).
Or, we could have just used: \[ \frac{f(3)}{72}=\frac{f(3)}{f(6)} = \frac{(3)^2}{(6)^2} \]
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