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Mathematics 10 Online
OpenStudy (anonymous):

Solve and graph: |x| + 1<2

OpenStudy (anonymous):

To solve it... \[ |x|+1<2 \]becomes: \[ \begin{split} x+1<2 &\text{ and }&-x+1<2 \end{split} \]

OpenStudy (anonymous):

@wio knows his stuffs.

OpenStudy (anonymous):

Hmm, okay. I remember that part from my teacher

OpenStudy (anonymous):

so what do you get when solving for \(x\)?

OpenStudy (anonymous):

GOT IT, on my paper that is. Thanks dude!

OpenStudy (anonymous):

cool

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