Question

Marilyn invested $5000 for one year, at 10% annual interest. Bert also invested $5000 for one year. His interest for the year was $125 more than Marilyn's interest for the year. What was his annual rate of interest?

Answer 1

Any ideas?

Answer 2

Marilyn's interest is 10% of $5,000 = $500

Answer 3

Bert's interest is $125 + $500 = $625.

What percent is 625 of 5,000?

Answer 4

$$\large \frac{x}{100}=\frac{625}{5,000}$$

Answer 5

12.5% ?\[\frac{ x }{ 100 } =\frac{ 625 }{ 5000 } 5000x=625(100)\]

Answer 6

Yes, 12.5% is the answer :)

Answer 7

\[x=125\]

Answer 8

Thanks you're a big help!

Answer 9

Thanks for asking :)