Question

logx+log(3x-1)=1

Answer 1

Lmao. Just use \(\log(a) +\log(b)=\log(ab)\)

Answer 2

\(\log(x) + \log(3x-1)=1 \\\log(x(3x-1))=1\\\log(3x^2-x)=1\\10^{\log(3x^2-x)}=10^1\\3x^2-x=10\\3x^2-x-10=0\)

Answer 3

Can you solve @strykez ?

Answer 4

@JackAttack log(x) is a function, it is not a number * x.

so this does not really makes sense \(\log \times (3x)\)

Answer 5

Oh, sorry. Just ignore mine :I

Answer 6

No worries, just explaining my ? :)

Answer 7

Okay