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find the angle the normal makes with the positive x axis 3x-2y-1=0
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any thoughts?
well i know that its tanx=3sqroot13/13/2sqroot13/13, i just dont know how to get the angle
a normal and a tangent are 90 degrees from each other ... they are perpendicular. depending on how you are finding these things .... gradient f defines the normal:\[\nabla f=(f_x,f_y)\] in this case: (3,-2)
|dw:1418239196219:dw|
quite frankly, the arctangent of (-2/3) seems apprpriate
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