Question

find a cubic function with zeros at -1 and -2 i - 3. do I write my imaginary zeros as (x-(-2i-3), (x-(-2i+3) or (x-(-2i-3) and (x+(-2i-3)?

Answer 1

I'm thinking that if you took the product of (x+1)(x+3)(x+2i) would result in a solution. Assuming x is real you would come up with\[x ^{3}+4x ^{2}+i(2x ^{2}+8x+6)+3x\]