find a bound on the real zeros of the polynomial function f(x)=x^4-8x^2-9
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x^4-8x^2-9 Factor out x^2(x^2-x-9) Leaves you with (x+1)(x-9); so your zero's would be (-1) and 9, no?
Sorry, x^2 (x^2-8x-9) x.x
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